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A total of 28 tickets for the summer fair were sold. A child ticket costs $2.50 and an adult ticket costs $3.75. If the total cost of the tickets sold is $82.50, how many child tickets were sold?

User Thomasina
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1 Answer

2 votes

Answer:

18 tickets were sold

Explanation:

The sum of the child tickets, C, and the adult tickets, A, is 28.

Stated algebraically:

C+A=28

The cost per child’s ticket is $2.50 and the cost per adult’s ticket is $3.75, and the total cost was $82.50.

Stated algebraically:

2.5C+3.75A=82.5

Multiply the first equation by −3.75 and use the method of elimination to directly solve for C:

−3.75C−3.75A=−105, which can be added to the second equation in order to eliminate the C variable:

2.5C+(−3.75C)+3.75A+(−3.75A)=82.5+(−105), which becomes:

−1.25C=−22.5, so C=18

User Esen
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