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Find the 22nd term of the sequence described by the

explicit formula:
f(n) = 8 + 3(n - 1)

Find the 22nd term of the sequence described by the explicit formula: f(n) = 8 + 3(n-example-1
User KanUXD
by
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1 Answer

5 votes

Answer:


\boxed{\boxed{\pink{\bf \leadsto The \ 22nd \ term \ is \ 71. }}}

Explanation:

Given that the nth term of the Arthemetic Sequence is given by :-


\implies f(n) = 8 + 3(n-1)

And we need to find the 22nd term .

So in place of n substitute 22 .


\bf\implies f(n) = 8 + 3(n-1) \\\\\bf\implies f_(22) = 8 + 3(22-1) \\\\\bf\implies f_(22) = 8 + 3* 21 \\\\\bf\implies f_(22) = 8 + 63 \\\\\bf\boxed{\bf\implies f_(22) = 71 }

Hence the 22nd term is 71 .

User Federick Jonathan
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