Question

Five years ago Janeta age was one_fifth of her mother'sage .Now she is one_third of her mother's age.Find their present ages?

Answer 1

J - Janeta's age M - mother's age

A) (J-5) = .2 * (M-5)

B) J = (1/3) * M

Subtracting 5 from both sides of B:

B) J -5 = (1/3)M -5

then we substitute the right side of this into the left side of A and we get

(1/3)M -5 = .2 M -1

.333333333333M -5 = .2M -1

.1111111111111111111M = 4

Mother's Age = 36

Janeta's Age = 12

Explanation: