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What is the average rate of change for the function f(x)=3(0.25)^x over the interval -2 ≤ x ≤ 0

User Rodling
by
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1 Answer

5 votes
Answer:
-22.5


Explanation:
Use the average rate of change equation
f(b)-f(a) / b-a
f(b) = f(0) = 3(.25)^0 = 3
f(a) = f(-2) = 3(.25)^-2 = 48

(3-48)/ 0-(-2)
(-45) / 2
-22.5
User Yucel Bayram
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6.5k points