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For the right triangle shown match the equivalent expressions.

For the right triangle shown match the equivalent expressions.-example-1

2 Answers

4 votes

Answer:

The one above me is correct

Explanation:

I just wanted people to get the right answer

User Jwpol
by
5.8k points
3 votes

Answer:

Part a)
cos(A)=sin(B)

Part b)
cos(B)=sin(A)

Part c)
sin(A)=cos(B)

Part d)
sin(B)=cos(A)

Explanation:

we know that

In the right triangle ABC of the figure


A+B=90\° ----> by complementary angles

so


cos(A)=sin(B)


sin(A)=cos(B)

Part a) Cos(A)


cos(A)=sin(B)


cos(A)=(5)/(13)

The value of cosine of angle A is the ratio between the adjacent side angle A to the hypotenuse

Part b) Cos(B)


cos(B)=sin(A)


cos(B)=(12)/(13)

The value of cosine of angle B is the ratio between the adjacent side angle B to the hypotenuse

Part c) Sin(A)


sin(A)=cos(B)


sin(A)=(12)/(13)

The value of sine of angle A is the ratio between the opposite side angle A to the hypotenuse

Part d) Sin(B)


sin(B)=cos(A)


sin(B)=(5)/(13)

The value of sine of angle B is the ratio between the opposite side angle B to the hypotenuse

User SonicProtein
by
6.4k points