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Pleaseee help me....what will the y-coordinate of b' if ab is dilated by a factor of 2/5, centered at the origin. A=(2,2) B=(10,2)

Pleaseee help me....what will the y-coordinate of b' if ab is dilated by a factor-example-1
User Marylynne
by
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2 Answers

6 votes

Answer:

The y-coordinate of point B' is
(4)/(5) or 0.8.

Explanation:

If a figure dilated by scale factor k, centered at the origin, then


(x,y)\rightarrow(kx,ky)

It is given that the coordinates of A are (2,2) and coordinates of B are (10,2).

The scale factor is
(2)/(5), so the coordinates of image are


A(2,2)\rightarrowA'((2)/(5)(2),(2)/(5)(2))\Rightarrow A'((4)/(5),(4)/(5))=A'(0.8,0.8)


B(10,2)\rightarrowB'((2)/(5)(10),(2)/(5)(2))\Rightarrow B'(4,(4)/(5))=B'(4,0.8)

Therefore the y-coordinate of point B' is
(4)/(5) or 0.8.

User Lscoughlin
by
7.9k points
3 votes

Answer:

The y-coordinate of B' is equal to 2

Explanation:

step 1

Find the distance of AB


AB=10-2=8\ units

step 2

Find the length of A'B'

Multiply the length of AB by the scale factor


A'B'=8*(2)/(5)= 3.2\ units

step 3

Find the midpoint AB


M=((2+10)/(2),(2+2)/(2) )


M=(6,2)

step 4

Find the x-coordinate of B'

The x-coordinate of B' is equal to the x-coordinate of midpoint plus the semi distance A'B'


6+(3.2)/(2)=6+1.6=7.6

Find the y-coordinate of B'

The y-coordinate of B' is equal to 2 (because is a horizontal line)

User Fanruten
by
8.8k points

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