Question

A rock is thrown from a cliff into a ravine the function h(t)=-16t^2 +192t + 2560 Describes the height in feet of the rock t seconds After it is thrown. what is the height of the rock in feet eight seconds after it is thrown?

Answer 1

`3,072\ ft`

Explanation:

we have

`h(t)=-16t^(2) +192t+2,560`

where

h -----> is the height in feet of the rock

t -----> the time in seconds

For
`t=8\ sec`

substitute the value of t in the function and find the value of h

`h(8)=-16(8)^(2) +192(8)+2,560=3,072\ ft`