Answer:
The area of rectangle ABCD is 198 square inches.
Explanation:
It is given that rectangle ABCD is congruent to rectangle HGJK.
The corresponding parts of congruent figure are congruent.
(CPCTC)
(Property of congruent)
In rectangle ABCD the length of the rectangle is 11 inches and width of the rectangle is 18 inches.
The area of a rectangle is
![A=length* width](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oyttaysegn248lhd8727v9w31hp9edwp3d.png)
The area of rectangle ABCD is
![A=AB* AD](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2s4ffhmicuiho4q6jxt1kudunztc3lbnby.png)
![A=11* 18](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d1wnfh8bsqxfk2uf8kys3r1f6eafscrezq.png)
![A=198](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kslbwvptm4s66hh3cxckudguhts637ie1h.png)
Therefore the area of rectangle ABCD is 198 square inches.