Question

Kelly has 236 feet of fence to use to enclose a rectangular space for her dog. She wants the width to be 23 feet. Draw a rectangle that could be the space for Kelley's dog. Label the length and the width

Answer 1

The draw in the attached figure

Explanation:

Let

L-----> the length of the rectangle

W----> the width of the rectangle

we know that

The perimeter of a rectangle is equal to

`P=2(L+W)`

we have

`W=23\ ft`

so

`P=2L+46` -----> equation A

`P\leq 236\ ft` ----> inequality B

substitute equation A in the inequality B and solve for L

`2L+46\leq 236`

`2L\leq 236-46`

`2L\leq 190`

`L\leq 95\ ft`

The maximum possible value of L is 95 ft

therefore

The rectangle could be

Length 95 ft

Width 23 ft

see the attached figure to see the draw