Question

Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effective in pulling the sled horizontally along the ground?

Answer 1

1.88 N

Step-by-step explanation:

Given in the question,

force applied by Jason = 4N

angle which it make with the ground = 62°

The angle made with the x-axis is cosine of the angle 62°

Thus, the horizontal component of the force is equal to

F = 4.00(cos62⁰) = 1.88 N

/

/

4N /

/

/ 62°

Ф ------------------------

by using trigonometry identity

cosФ = adjacent / hypotenuse

horizontal force = hypotenuse (cos(Ф))

horizontal force = 4cos(62)