Question

Plz help me with this

Answer 1

`(31x)/(30)`

Explanation:

Before adding we require the fractions to have a common denominator

The lowest common denominator of 2, 5 and 3 is 30, thus

`(15x)/(15(2))` +
`(6x)/(6(5))` +
`(10x)/(10(3))`

=
`(15x)/(30)` +
`(6x)/(30)` +
`(10x)/(30)`

Add the numerators leaving the denominator

=
`(15x+6x+10x)/(30)` =
`(31x)/(30)`

Answer 2

Answer:
`\bold{c)\quad (31x)/(30)}`

Explanation:

`(x)/(2)+(x)/(5)+(x)/(3)\\\\\text{The LCD of 2, 5, and 3 is }2\cdot 5\cdot 3=30\\\text{Multiply each term so their denominator is 30:}\\\\\\(x)/(2)\bigg((15)/(15)\bigg)+(x)/(5)\bigg((6)/(6)\bigg)+(x)/(3)\bigg((10)/(10)\bigg)\\\\\\=(15x)/(30)+(6x)/(30)+(10x)/(30)\\\\\\=(15x+6x+10x)/(30)\\\\\\=\large\boxed{(31x)/(30)}`