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∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 25°, minor arc AB = 115°, and minor arc DE = 115°, what is the measure of ∠ACE? A) 12.5° B) 40° C) 45° D) 52.5°

User Predelnik
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1 Answer

4 votes

Answer:

The measure of angle ACE = 40° ⇒ answer (B)

Explanation:

* Lets explain some information

- A secant is a line that intersects a circle in exactly two points.

- When two secants, intersect each other outside a circle,

then the measure of the angle formed is one-half the positive

difference of the measures of the intercepted arcs.

* Now the two secants AB and ED intersect each other outside

the circle at point C and formed angle ACE

- Angle ACE intercepted by two minor arcs. arc BD and arc AE

- The measure of angle ACE is one-half the positive difference

of the arcs BD and AE

* Lets calculate the measures of the arcs to find the measure

of the angle

∵ The measure of minor arc AB = 115°

∵ The measure of minor arc BD = 25°

∵ The measure of minor arc DE = 115°

∵ The measure of the circle is 360°

∴ The measure of arc AE = 360 - (115 + 25 + 115) = 360 - 255 = 105°

* Now we can find the measure of angle ACE

∵ m∠ACE = (1/2)(measure of arc AE - measure of arc BD)

∴ m∠ACE = (1/2)(105 - 25) = (1/2)(80) = 40°

* The measure of angle ACE = 40°

User Mpjjonker
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