Answer:
![y=(-3)/(2)x-4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l9o1ypn92gfj3pm1y4fby00zmpjzvskc83.png)
Explanation:
the equation of the line perpendicular to 2x – 3y = 13
It passes through the point (–6, 5)
![2x -3y = 13](https://img.qammunity.org/2020/formulas/mathematics/middle-school/295iiw046igq9imvil9wdnzbyvtgim2szq.png)
Subtract 2x from both sides
![-3y =-2x+13](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vmop4dq0ysrxbzmbtw92jjbw0kqmmklvg3.png)
Divide both sides by -3
![y=(2)/(3)x-(13)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qvcufuz1hezuzkawle7xqipo09qgqu0oya.png)
Slope = 2/3
Slope of perpendicular lines are negative reciprocal of one another
slope of perpendicular line is
![(-3)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/systb1h2gfgzy3lfpu490iuttrzn1v8f2c.png)
Point (-6,5)
![y-y1=m(x-x1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/38rsw060gekfjbf76g57jsb45ginj88wcy.png)
![y-5=(-3)/(2)(x+6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mmc8kob4lc59gciy45ywpae7rc58b4430e.png)
![y-5=(-3)/(2)x-9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iev7bax7k0oxmpqg3hbsm3y66ou21fdbcc.png)
Add 5 on both sides
![y=(-3)/(2)x-4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l9o1ypn92gfj3pm1y4fby00zmpjzvskc83.png)