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Which function is most likely graphed on the coordinate plane below? What is the equation of the line perpendicular to 2x – 3y = 13 that passes through the point (–6, 5)?

Y=2/3 x +9
Y=-3/2x-4
Y=-3/2 x -13
Y=2/3x-1

User Knaperek
by
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1 Answer

7 votes

Answer:


y=(-3)/(2)x-4

Explanation:

the equation of the line perpendicular to 2x – 3y = 13

It passes through the point (–6, 5)


2x -3y = 13

Subtract 2x from both sides


-3y =-2x+13

Divide both sides by -3


y=(2)/(3)x-(13)/(3)

Slope = 2/3

Slope of perpendicular lines are negative reciprocal of one another

slope of perpendicular line is
(-3)/(2)

Point (-6,5)


y-y1=m(x-x1)


y-5=(-3)/(2)(x+6)


y-5=(-3)/(2)x-9

Add 5 on both sides


y=(-3)/(2)x-4

User LLS
by
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