Answer:
![185.43 mm^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/qoe9wy85mqcct49ecx9ym9e36uqjhln60n.png)
Explanation:
Radius of semicircle = 8.5 mm
Area of semicircle =
![(\pi r^2)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5gmeipefla6ag7q0ibub6cgglci1f2kxtw.png)
=
![(3.14 (8.5)^2)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/15w03nzga6jxmysy1bjr9e6wgruu205mre.png)
=
![113.4325 mm^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/ivalksinxrhzg0pwv62pqhof7avi3e24og.png)
Area of triangle =
![(1)/(2) * Base * Height](https://img.qammunity.org/2020/formulas/mathematics/high-school/xscxz4c5co69x3sgd7t3ht9jhjk0nki2sh.png)
Area of triangle in figure=
![(1)/(2) * 12 * 12](https://img.qammunity.org/2020/formulas/mathematics/high-school/4ahxjllkiou29nsmcvpudusa8omd7yilid.png)
=
![72 mm^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/i1zj7il4t261om671wi05zyp7x1ytu1ubt.png)
So, Area of the figure = Area of semicircle +Area of triangle
=
![113.4325 mm^2+72 mm^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/l0ekqogam0hitjox7uc332qrb9cqvir91x.png)
=
![185.43 mm^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/qoe9wy85mqcct49ecx9ym9e36uqjhln60n.png)
Thus Option B is correct.
Hence the total area of the composite figure rounded to the nearest hundredth is
![185.43 mm^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/qoe9wy85mqcct49ecx9ym9e36uqjhln60n.png)