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Compare the average rate of change for both functions over the interval [0,3].

G(x)=-x^2-5x +3 and H(x)=- 8x +10

1 Answer

1 vote
So find g(0) and g(3)
G(0) = 0^2 -5(0) +3 = 3
And g(3) = 3^2 - 5(3) +3 = 9 - 15 + 3 = 3 so there is no change in g(x) for that interval.

H(0) = 8(0) + 10 = 10
And h(3) = 8(3) + 10 = 34
So the change in h(x) for that interval is 24.
User Abhishek Prabhat
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