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Consider the graph of the following quadratic equation y=-xpower of 2 - 10x + 24 What is the y-value of the vertex

User Shnkc
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Answer:

The y-value of the vertex is 49

Explanation:

The given quadratic function is


y=-x^2-10x+24

We complete the square to find the vertex.

First factor
-1 from the first two terms.


y=-(x^2+10x)+24

Add and subtract the square of half the coefficient of x.


y=-(x^2+10x+5^2-5^2)+24


y=-(x^2+10x+5^2)--5^2+24

Recognize the perfect square trinomial.


y=-(x+5)^2+25+24


y=-(x+5)^2+49

The function is now of the form;


y=a(x-h)^2+k, where (h,k)=(-5,49) is the vertex.

The y-value of the vertex is 49

User Tamuna
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