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Solve x^2- 2x - 4 = 0

2 Answers

1 vote

Answer:

yes

Explanation:

User Jason Congerton
by
4.1k points
4 votes

Answer:


\displaystyle x= 1\pm √(5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula:
    \displaystyle x=(-b\pm√(b^2-4ac) )/(2a)

Explanation:

Step 1: Define

x² - 2x - 4 = 0

Step 2: Identify Variables

a = 1

b = -2

c = -4

Step 3: Solve for x

  1. Substitute [QF]:
    \displaystyle x=(2\pm√((-2)^2-4(1)(-4)) )/(2(1))
  2. Exponents:
    \displaystyle x=(2\pm√(4-4(1)(-4)) )/(2(1))
  3. Multiply:
    \displaystyle x=(2\pm√(4+16) )/(2)
  4. Add:
    \displaystyle x=(2\pm√(20) )/(2)
  5. Simplify:
    \displaystyle x=(2\pm 2√(5) )/(2)
  6. Factor:
    \displaystyle x=(2(1\pm √(5)) )/(2)
  7. Divide:
    \displaystyle x= 1\pm √(5)
User Entropy
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