Question

A soccer ball is kicked upward from a hill and then falls to the ground. The height, in feet, of the ball after t sec is modeled by the function h(t) = –16t2 + 26t +12. What is the initial height of the ball?

Answer 1

answer is 12 feet c

Explanation:

Answer 2

Answer: The initial height of the ball is 12 feet.

Explanation:

We have the function
`h(t)=-16t^2+26t+12`, which models the height (in feet) of the ball after
`t` seconds.

Then, as the height is in function of the time, we know that the ball is in the initial height when:

`t=0`

So, to find the initial height, you need to substitute
`t=0` into the function:

`h(0)=-16(0)^2+26(0)+12\\\\h(0)=0+0+12\\\\h(0)=12`

Therefore, the initial height of the ball is 12 feet.