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Total crimes 21,790,654. Roberry is 408, 016 and Burglary is 2,050,992 What are their percent in crimes rounded to the nearest percent for each two crimes

User GSite
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1 Answer

3 votes

Answer:

Percent of Robbery
=2 \%

Percent of Robbery
=9 \%

Explanation:

Given that total number of crimes = 21,790,654.

total number of Robbery = 408, 016 and

total number of Burglary = 2,050,992

Now we need to find about what are their percent in crimes rounded to the nearest percent for each two crimes.

So apply the percent formula


Percent=(Part)/(Whole)* 100 \%

Then percent of Robbery
=(408016)/(21790654)* 100 \%=0.01872* 100 \%=2 \%

Then percent of Robbery
=(2050992)/(21790654)* 100 \%=0.094122* 100 \%=9 \%

User PraneetNigam
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