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MATH HELP PLEASE! I NEED HELP IM DUMB

MATH HELP PLEASE! I NEED HELP IM DUMB-example-1
User DeFreitas
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First of all...YOU'RE NOT DUMB!!! You just need some help! Being confident in your knowledge/skills is half the work! ;D

And second...

PART 1:

28. Polygon ABCDE is a pentagon (it has five sides). The sum of the interior angle measures for a pentagon is 540°. Here's what we know:

m<A = 90°

m<B = 90°

m<D = 90°

m<C = m<E

First, find the sum of the measures of angles A, B, and D.

(90)(3) = 270°.

Next, find the combined angle measure of angles C and E.

540 - 270 = 270°.

Finally, find the measure of angle E (or m<AED).

270 / 2 = 135°.

So, to fill in the blanks:

90 · 3 + x · 2 = 540

m<AED = 135°.

29.

(a) 360°

(b) hexagon

(c) 1080

(d) hendecagon (11 sides)

I have attached a table containing a list of polygons, their side-count, and the sum of their interior angles.

PART 2:

Complimentary angles are angles whose measures add to equal 90°.

Supplementary angles are angles whose measures add to equal 180°.

30. 35° + 55° = 90°; Complimentary.

31. 62° + 108° = 170°; Neither.

Hope this helps!

MATH HELP PLEASE! I NEED HELP IM DUMB-example-1
User Sigman
by
6.0k points