ANSWER
1199
EXPLANATION
The given series is
![\sum_(n=9)^(30)(3n-4)](https://img.qammunity.org/2020/formulas/mathematics/high-school/bt8dl7id5t47oetw9w692ubv26rpa8twjb.png)
To find the first term of this series, we put n=9 into the formula.
![a = 3(9) - 4 = 23](https://img.qammunity.org/2020/formulas/mathematics/high-school/nu1vjvk2dzmevzsav300j9pomp3fyl01ux.png)
To find the last term, we put n=30
![l = 3(30) - 4 = 86](https://img.qammunity.org/2020/formulas/mathematics/high-school/s61qcqafts807l593nsle0681xq012iv3s.png)
There are 22 terms from the 9th term to the 30th term
The sum of the consecutive n-terms of an arithmetic series is given by;
![S_n= (n)/(2) (a + l)](https://img.qammunity.org/2020/formulas/mathematics/high-school/gw4ngw3aati3p9kk2z5hrmp3wr36zrarpz.png)
We substitute n=22, a=23, and l=86 to get;
![S_ {22}= (22)/(2) (23 + 86)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qjk70djtoezc8xi44sxmqzx5ei9ohbx8c8.png)
![S_ {22}= 11 * 109](https://img.qammunity.org/2020/formulas/mathematics/high-school/ch5c5m0rztyts8sr8djj9iovrh3yng7eoc.png)
![S_ {22}= 1199](https://img.qammunity.org/2020/formulas/mathematics/high-school/e74phy8p9psatx9dney80gn1wjoaqygqtq.png)