Question

What is the standard form of (7-5i)(2+3i)?

Answer 1

The Stanford form is

29+11i

Answer 2

The standard form is
`=29+11i`

Explanation:

We need to write the provided expression in standard form

Given expression is
`(7-5i)(2+3i)`

first simplified the
`(7-5i)(2+3i)`

`\mathrm{Apply\:complex\:arithmetic\:rule}:\quad \left(a+bi\right)\left(c+di\right)=\left(ac-bd\right)+\left(ad+bc\right)i`

`a=7,\:b=-5,\:c=2,\:d=3`

`=\left(7\cdot \:2-\left(-5\right)\cdot \:3\right)+\left(7\cdot \:3+\left(-5\right)\cdot \:2\right)i`

further simplify

`=29+11i`

Therefore, the standard form is
`=29+11i`