Question

Find the period of the function.
y= 3 sin x/8

Answer 1

B. 16π

Explanation:

Given a function in the form;

y = A sin(B(x + C)) + D

Then;

Amplitude is A and Period is 2π/B

In our case; the function is y = 3 sin(x/8)

Therefore; B = 1/8

Hence; Period = 2π/(1/8)

= 16π

Answer 2

option b

16π

Explanation:

Given in the question an equation,

y = 3sin(x/8)

We know that, the period of y = asin(bx) is given by

Period =
`(2\pi )/(|b|)`

here,

a = 3

b = 1/8

so,

Period = 2π / (1/8)

= 8(2π)

= 16π

The period of the function is 16π .