181k views
3 votes
There are no solutions to the system of inequalities shown below

y<4x-6
Y>4x+2

A.true
B.false

1 Answer

7 votes

Answer:

A. True

Explanation:

<, > - dot line

≤, ≥ - solid line

<, ≤ - shading to the left

>, ≥ - shading to the right

=======================================

y < 4x - 6 → y = 4x - 6

for x = 0 → y = 4(0) - 6 = 0 - 6 = -6 → (0, -6)

for x = 2 → y = 4(2) - 6 = 8 - 6 = 2 → (2, 2)

y > 4x + 2 → y = 4x + 2

for x = 0 → y = 4(0) + 2 = 0 + 2 = 2 → (0, 2)

for x = -1 → y = 4(-1) + 2 = -4 + 2 = -2 → (-1, -2)

Look at the picture.

NO SOLUTION

Other method:

We have the lines y = 4x - 6 and y = 4x + 2. The slopes of lines are the same. Therefore the lines are parallel.

y < 4x - 6 → shadded to the left from the line

y > 4x + 2 → shadded to right from the line

Shaded regions do not have a common part. Therefore, there are no solutions.

There are no solutions to the system of inequalities shown below y<4x-6 Y>4x-example-1
User Ayorgo
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories