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How many moles are in 1.806 x 1024 molecules of bromine?

User Ruka
by
4.8k points

2 Answers

9 votes

Answer:


\boxed {\boxed {\sf About \ 2.999 \ moles \ of \ bromine}}

Step-by-step explanation:

To convert from moles to molecules, we must use Avogadro's Number.


6.022*10^(23)

This tells us the number of particles (atoms, molecules, ions, etc) in 1 mole. In this problem, the particles are molecules of bromine in 1 mole of bromine.


6.022*10^(23) \ molecules \ Br / 1 \ mol \ Br

1. Convert from moles to molecules

Use Avogadro's number as a fraction or ratio.


(6.022 *10^(23) \ molecules \ Br)/(1 \ mol \ Br)

Multiply this fraction by the given number of bromine molecules.


1.806 *10^(24) molecules \ Br *(6.022 *10^(23) \ molecules \ Br)/(1 \ mol \ Br)

Flip the fraction so the molecules of bromine can cancel out.


1.806 *10^(24) \ molecules \ Br* (1 \ mol \ Br)/(6.022 *10^(23) \ molecules \ Br)


1.806 *10^(24) * (1 \ mol \ Br)/(6.022 *10^(23))

Multiply and condense the expression into 1 fraction.


(1.806 *10^(24) \ mol \ Br)/(6.022 *10^(23) )

Divide.


2.999003653 \ mol \ Br

2. Round

The original measurement, 1.806*10^24 has 4 significant figures (1, 8, 0, and 6). We must round our answer to 4 sig figs. For the answer we found, that is the thousandth place.


2.999003653 \ mol \ Br

The 0 in the ten-thousandth place tels us to leave the 9 in the thousandth place.


\approx 2.999 \ mol \ Br

There are about 2.999 moles of bromine in 2.806 *10^23 molecules.

User Lorenzo P
by
4.7k points
4 votes

Answer:

2.999 mol Br

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

1.806 × 10²⁴ molecules Br

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert


\displaystyle 1.806 \cdot 10^(24) \ molecules \ Br((1 \ mol \ Br)/(6.022 \cdot 10^(23) \ molecules \ Br) ) = 2.999 mol Br

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

Our final answer is already in 4 sig figs, so there is no need to round.

User Pygabriel
by
4.5k points