Question

The distance of one lap around a school track is \frac{1}{4} mile. Sherrie walks 5 laps around the track. How many more laps must Sherrie walk to reach a total distance of 3.5 miles?

Answer 1

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Explanation:

Answer 2

Answer: Sherrie must walk 9 more laps.

Explanation:

You know that one lap around the school track is
`(1)/(4)mile` or 0.25 miles.

Let be
`d_1` the distance in miles that Sherrie walks in 5 laps.

To calculate
`d_1` you need to multiply 0.25 miles by 5. Then:

`d_1=(0.25miles)(5)\\d_1=1.25miles`

Let be
`d_2` the distance left that Sherrie must walk to reach a total distance of 3.5 miles.

To calculate
`d_2` you need to subtract 3.5 miles and 1.25 miles. Then:

`d_2=3.5miles-1.25miles\\d_2=2.25miles`

Let be
`x` the number of more laps that she must walk to reach a total distance of 3.5 miles.

If she needs to walk 2.25 miles more to reach a total distance of 3.5 miles and 1 lap is 0.25 miles, then "x" is:

`x=(2.25miles)/(0.25miles)\\\\x=9`

She must walk 9 more laps.