3.0k views
4 votes
Please help me with this geometry question

Please help me with this geometry question-example-1
User Sorak
by
8.7k points

1 Answer

3 votes

Answer:


180+18√(3)\ in^2.

Explanation:

The surface area of right triangular prism is the sum of area of two base triangles and 3 area of side rectangles.

The area of base triangle is


A_(base)=(a^2√(3))/(4),

where a is the length of the side of equilateral triangle. In your case, a=6 inches. Thus,


A_(base)=(6^2\cdot√(3))/(4)=9√(3)\ in^2.

The area of side rectangle is


A_(side)=ah,

where h is the height of the rectangle. In your case, h=10 inches. Thus,


A_(side)=6\cdot 10=60\ in^2.

Hence, the surface area is


SA=2\cdot 9√(3)+3\cdot 60=180+18√(3)\ in^2.

User Dan Bliss
by
8.0k points