Answer:
Difference between graphs of both equation is the vertex of the both curves.
Explanation:
Given Equations of curves are
![y=-3x^2+2\:\:and\:\:y=-3x^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yb5935j8v2a6v5q1kif2i2xk9lai6um3dn.png)
We need to find the difference in the graphs of the given curves.
one variable in both curves has degree 2 and 2nd variable in both curves has degree 1.
So, Given Equation of curves are of parabola.
Consider 1st equation,
y = -3x² + 2
![x^2=(-1)/(3)(y-2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/isp50xu0cz6g55ag630qmd8xc2y4ledwxe.png)
Vertex of this parabola is ( 0 , 2 )
Axis of symmetry is y-axis.
Consider 2nd equation,
y = -3x²
![x^2=(-1)/(3)y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yykm01ouph7yjrojp0nah3pboi8snbxma9.png)
Vertex of this parabola is ( 0 , 0 )
Axis of symmetry is y-axis.
Therefore, Difference between graphs of both equation is the vertex of the both curves.
Figures are attached.