Question

Write the equation of a line that is perpendicular to y=3/2x+2 that goes through (6,-3)

Answer 1

`y + 3 = -(2)/(3)(x-6)`

Explanation:

Perpendicular lines are lines which intersect at 90 degrees which have negative reciprocal slopes. The slope of the line y = 3/2x + 2 is 3/2. The slope of the line perpendicular to it will be -2/3. Substitute m = -2/3 and (6,-3) into the point slope form of a line.

`y - y_1 = m(x-x_1)\\y - -3 = -(2)/(3)(x-6)\\y + 3 = -(2)/(3)(x-6)`