Question

The graph of a logarithmic has a vertical asymptote at x=4 , contains the point (e+4, 1) , and has an x-intercept of 5. Which function is graphed?

Question options:

f(x) =ln(x−4)

f(x) =ln(x+4)

f(x) =lnx−4

f(x) =lnx+4

Answer 1

f(x) =ln(x−4)

Explanation:

We can easily solve this question by plotting each of the graphs and verify the conditions in the problem,

Please see attached image.

The answer is the first option

f(x) =ln(x−4)

Which corresponds to the function ln(x) shifted four units to the right.

Besides,

f(e+4) =ln(e + 4−4) = ln(e) = 1