reasoning: first you just have to draw a trapezoid with its parallel sides vertical. then make the left vertical side, which will represent the pole. taller than the vertical right side, which will represent the surveyors transit (which is 3 feet, so you have to label the side lengths as 3 feet) the horizontal line segment between the vertical sides has a length of 50 feet. Draw a horizontal line segment from the top of the right vertical side to the left vertical side. the segment that connects the top of the left vertical segment to the right vertical segment is measured at 26° degrees then have the side of the right triangle which has a base angle which is 26° degrees of an angle have length x (ft.).
↓↓↓↓↓(heres my work)↓↓↓↓↓
tan(26°) = x/150
150 tan(26°) = x
x ≈ 73.16 ft.
The length of the pole is 3 feet more than this, so to the nearest foot the pole is 76 ft. high.
HOPE THIS HELPS :)