Answer:
6750 J
Step-by-step explanation:
The specific heat capacity of iron is 450 J/kg/K
Quantity of heat = mcθ; where m is the mass and c is the specific heat capacity and θ is the temperature change.
Therefore;
m = 3 kg, c = 450 J/kg/K and θ = 5°C
Quantity of heat = 3 × 450 × 5
= 6150 Joules