Question

Need some math help!!!
Factor the polynomial by grouping: 12p^3 − 21 p^2 + 28p − 49

Answer 1

12p³ – 21p² + 28p – 49

3p²(4p–7) + 7(4p–7)

(4p–7)(3p+7)

Answer 2

`\left(4p-7\right)\left(3p^2+7\right)`

Explanation:

`12p^3-21p^2+28p-49`

`\left(12p^3-21p^2\right)+\left(28p-49\right)`

`7\left(4p-7\right)`

`3p^2\left(4p-7\right)`

`7\left(4p-7\right)+3p^2\left(4p-7\right)`

`\left(4p-7\right)\left(3p^2+7\right)`