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Using the method of completing the square, put each circle into the form


(x-h)^(2) + (y-k)^(2) = r^(2)
Then determine the center and radius of each circle


x^(2) + y^(2) +8x - 6y +16 = 0

1 Answer

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ANSWER

Center; (-4,3)

Radius: r=3

Step-by-step explanation

The given circle has equation;


x^(2) + y^(2) +8x - 6y +16 = 0

Rewrite to obtain;


x^(2) + y^(2) +8x - 6y = -16

Regroup to obtain;


x^(2) +8x + y^(2)- 6y = -16

Add the square of half the coefficient of the linear terms to both sides of the equation,


x^(2) +8x + (4)^(2) + y^(2)- 6y + {( - 3)}^(2) = -16+ (4)^(2) + {( - 3)}^(2)


(x + 4)^(2) + {(y - 3)}^(2) = -16+ 16 + 9

This simplifies to;


(x + 4)^(2) + {(y - 3)}^(2) = {3}^(2)

By comparison;


(-4,3)=(h,k)

and the radius is


r = 3

User Nico Spencer
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