Question

Which of the following linear equations corresponds to the table above?

OA. y=4x-3
OB. y=¹/4x-3
OC. y=¹/4x+3
OD.
y = 4x + 3

Answer 1

`given \: that \: its \: linear \\ m = (15 - 3)/(3 - 0) = (12)/(3) = 4`

`b = y(0) = 3 \\ y = 4x + 3 \:`

Option D

Answer 2

D) y = 4x + 3

Explanation:

Equation of line in slope y-intercept form:

`\sf \boxed{\bf y = mx +b}`

Here, m is the slope and b is y intercept.

At y intercept, x = 0

From the table, y intercept = 3

Choose any two points from the table to find the slope.

(0 ,3) & (3,15)

`\sf \boxed{\bf Slope =(y_2-y_1)/(x_2-x_1)}`

`\sf =(15-3)/(3-0)\\\\=(12)/(3)\\\\=4`

m = 4 ; b = 3

Equation of line:

y = 4x + 3