Question

What is the area of △ABC ?

Enter your answer, as a decimal, in the box.

Round only your final answer to the nearest tenth.

units²

Triangle A B C has leg A C labeled 13 and leg B C labeled 15. Angle A C B is labeled 30.5 degrees.

Answer 1

Thus, the area of the triangle ABC is 49.5 square units.

Explanation:

It is given that in a triangle ABC, the measure of the side AC is 13 and the measure of the side BC is 15 and the measure of the angle C is 30.5.

Thus, the area of the triangle ABC is given as:

`A={(1)/(2)}{*}AC{*}BC{*}sin(30.5)`

Substituting the given values, we have

`A={(1)/(2)}{*}13{*}15{*}(0.507)`

`A={(98.96)/(2)}`

`A=49.5 units^2`

Thus, the area of the triangle ABC is 49.5 square units.

Answer 2

49.5 units²

Explanation:

The applicable formula is ...

Area = 1/2·ab·sin(C) = (1/2)·15·13·sin(30.5°) ≈ 49.48499

≈ 49.5 . . . square units