Question

A patient requires an IV of D5W, a 5% solution of dextrose (sugar) in water. To the nearest milliliter, how much D20W, a 20% solution of dextrose in water, must be added to 100 milliliters of distilled water to produce a D5W solution? Please show all work.

Answer 1

`A=300ml`

Explanation:

From the question we are told that

5% solution of dextrose sugar in water

20% solution of dextrose in

100 milliliters of distilled water water

Generally in mathematically solving we call A the amount of D20W added

Since 20% of dextrose is needed

`20 \%*100=20milliter`

Total quantity after addition (100+x)

for DW5% total solution is

`5\% (100+A)= (5)/(100)(100+A)`

`5\% (100+A) =5+0.05A`

Mathematically

`5+0.05A =20`

`5+0.05A =20-5`

`A=(15)/(0.05)`

`A=300ml`

Therefore the required quantity
`A=300ml`