Question

Write h(x) = 7 + 10x + x2 in vertex form. Write h in standard form. h(x) = x2 + 10x + 7 Form a perfect square trinomial by adding and subtracting . h(x) = (x2 + 10x + 25) + 7 – 25 Write the trinomial as a binomial squared. Write the function in vertex form, if needed. What is h(x) = 7 + 10x + x2 written in vertex form?

h(x) = (x – 25)2 – 18

h(x) = (x – 5)2 + 32

h(x) = (x + 5)2 – 18

h(x) = (x + 25)2 + 32

Answer 1

Answer: is "c" on edg. your welcome ;)

Explanation:

Answer 2

h(x)=(x+5)^2-18

Explanation:

we know that

A quadratic function (vertical parabola) written in vertex form is equal to

y=(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

we have

h(x)=7+10x+x^2

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

h(x)-7=x^2+10x

Complete the square. Remember to balance the equation by adding the same constants to each side

h(x)-7+25=(x^2+10x+25)

h(x)+18=(x^2+10x+25)

Rewrite as perfect squares

h(x)+18=(x+5)^2

h(x)=(x+5)^2-18 ----> equation in vertex form

The vertex is the point (-5,-18)