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A hot iron ball is dropped into a 200. g sample of water initially at 50 0C. If 8.4 kJ of heat is transferred from the ball to the water, what is the final temperature of the water

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The final temperature of the water after dropping the iron ball has been 60.
The heat transferred by the iron ball can be given by:
Heat (Q) = mcT
Q = heat transferred = 8.4 kJ
Q = 8400 J
m = mass = 200 g
c = specific heat = 4.2 J/g.
T = change in tempertaure = Initial temperature - final temperature
T = Final temperature - 50
8400 J = 200 g 4.2 J/g. (Final temperature - 50 )
Final temperature = 60.
The final temperature of the water after dropping the iron ball has been 60.
User Marcel Hoekstra
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