Question

What is the equation of a line passing through (-6, 5) and having a slope of 1/3 ? A. B. C. D. y = 3x + 7

Answer 1

Equation of the line is,

y = x/3 + 7

Explanation:

It is given that,a line passing through (-6, 5) and having a slope of 1/3

Points to remember

The equation of a line passing through the point (x₁, y₁) with slope m is given by

(y - y1)/(x - x₁) = m

To find the equation of line

here x₁ = -6, y₁ = 5 and m = 1/3

(y - y1)/(x - x₁) = m

(y - 5)/(x - - 6) = 1/3

(y - 5)/(x + 6) =1/3

y = x/3 + 7

Answer 2

y = 1/3 x + 7

Explanation:

Given; the line is passing through, (-6,5) and the slope is 1/3

We can get its equation;

We would take, a point (x,y) and the given point (-6,5)

Therefore; Since slope = Δy/Δx

Then;

(5-y)/ (-6-x) = 1/3

3(5-y) = -6 -x

15 - 3y = -6 - x

we get;

3y = 6 + x + 15

3y = x + 21

Therefore;

y = 1/3 x + 7