1 Answer

Jukka · Answer 1 · 2020-05-22T05:10:00+0000

Answer:

The following as a single sine function of an angle:

$12 sin3\theta \cos3\theta cos 6\theta =3* \sin12\theta$

Explanation:

Given :
$12 sin3\theta \cos3\theta cos 6\theta$

Using identity:

$Sin2x=2* \sin x \cos x$

$=6* 2* sin3\theta \cos3\theta \cos 6\theta$

$=6* (2* sin3\theta \cos3\theta) \cos 6\theta$

$=6* \sin 6\theta \cos 6\theta$

$=3* (2* \sin 6\theta \cos 6\theta)$

$=3* \sin12\theta$

The following as a single sine function of an angle:

$12 sin3\theta \cos3\theta cos 6\theta =3* \sin12\theta$

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