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Secxcscx/cotx = sec^2x​
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Secxcscx/cotx = sec^2x​

Secxcscx/cotx = sec^2x​-example-1
User Bastibe
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1 Answer

3 votes

Answer:

see explanation

Explanation:

Using the trigonometric identities

• secx =
(1)/(cosx), cscx =
(1)/(sinx)

• cotx =
(cosx)/(sinx)

Consider the left side


(sexcscx)/(cotx)

=
(1)/(cosx) ×
(1)/(sinx) ×
(sinx)/(cosx)

Cancel the sinx on numerator/ denominator

=
(1)/(cos^2x)

= sec²x = right side ⇒ verified

User John Yates
by
5.5k points
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