Question

Secxcscx/cotx = sec^2x​

Answer 1

see explanation

Explanation:

Using the trigonometric identities

• secx =
`(1)/(cosx)`, cscx =
`(1)/(sinx)`

• cotx =
`(cosx)/(sinx)`

Consider the left side

`(sexcscx)/(cotx)`

=
`(1)/(cosx)` ×
`(1)/(sinx)` ×
`(sinx)/(cosx)`

Cancel the sinx on numerator/ denominator

=
`(1)/(cos^2x)`

= sec²x = right side ⇒ verified