Hello!
The answer is:
She still needs to ride
Why?
From the statement, we know that Nance's friend is 4 1/2 miles away and she only has ridden 2 3/5 miles.
So, let be "x" the distance that she still need to ride to get to her friend's house.
The equation will be:
![TotalDistance=RiddenDistance+x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v0rdu1eccamcvks36o9vdtj5dc4im4vj37.png)
Remember that:
![a(b)/(c)=a+(b)/(c)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xt0ca7s14dxlf4nesp278lbq1azj5nv2gp.png)
Also, if we need to add/substract fractions we must remember that:
![(a)/(b)+(c)/(d)=(ad+bc)/(bd)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/id39g04qmmdsg6klis1n7tk023hqflsogo.png)
If we need to switch fractions to mixed numbers, we need to:
- Perform the division
- Keep the whole number and make a fraction with the aproximated next whole number (remainder) as numerator, and the original denominator. We need to use the remainder to approximate to the next whole number.
![(a)/(b)=c.r](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l2rrvce6ydui5o7x06auwjjmk6lp2tiq7c.png)
Where:
![a=numerator\\b=denominator\\c=WholePart\\r=NextWholeNumber](https://img.qammunity.org/2020/formulas/mathematics/middle-school/it15p4kxv5pkzrqbepeb9jw34b5qmwj8ue.png)
So,
![(a)/(b)=c(r)/(b)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/627pf0etacidnihymu2k2gglilggty85az.png)
Then, substituting the given information into the equation, we have:
![4(1)/(2) =2(3)/(5) +x\\\\x=(4(1)/(2)) -(2(3)/(5))=4+(1)/(2)-2-(3)/(5)=2+(1)/(2)-(3)/(5)\\\\x=2+(1)/(2)-(3)/(5)=2+(5-6)/(10)=2-(1)/(10)\\\\x=2-(1)/(10)=(20-1)/(10)=(19)/(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fouw6iiqtpmhxrb0usez5sj24jp7c9hz94.png)
So, she still need to ride
![(19)/(10)miles](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x8odpummu8gxhuqqg50d40a90pdm31ecxa.png)
or
To prove if the answer is reasoable, let's substituite the obtained value into the equation and check if the equation is satisfied:
![4(1)/(2)=2(3)/(5)+1(9)/(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2ifzly1w4h8tzyyxa09y4d71q6fasxqrfy.png)
![4(1)/(2)=(13)/(5)+(19)/(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/omn04jh49v3f3hcxbkuktzhcbsqkcw0z15.png)
![4(1)/(2)=(9)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rzb84gxj1xr5awa175qm4n45ib52wjldu1.png)
![4(1)/(2)=4(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u1eaih22ey8wy9f5kqh7j2g7u0h5ru42ij.png)
Have a nice day!