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5 votes
What is the solution to the following equation? x^2-3x-10=0

A= x=5 or x=-2

B= x=2 or x=-5

C= x=2 or x=5

D= x=-2 or x=-5

User Redacted
by
4.9k points

2 Answers

5 votes

x^2 - 3x -10 = 0

Find two numbers when added together = -3 and when multiplied = -10

-5 + 2 = -3

-5 * 2 = -10

Now write the factored form of the equation:(x-5) (x+2) = 0

Solve for each x so that the equation = 0:

5 -5 = 0

-2 + 2 = 0

So X = -2 or 5

The answer is A.

User Radoslav Hristov
by
5.1k points
4 votes

Answer:

A= x=5 or x=-2

Explanation:

x^2-3x-10=0

Factor

What 2 numbers multiply together to give you -10 and add together to give you -3

-5*2 = -10

-5+2 = -3

(x-5) (x+2) =0

Using the zero product property

x-5 =0 x+2 =0

x-5+5=0+5 x+2-2=0-2

x=5 x=-2

User NicolasP
by
5.4k points
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