Question

Find the average braking force of a 1000 kg car moving at 10 m/s braking to a stop in 5 s.

Answer 1

-2000 N

Step-by-step explanation:

To solve the problem, we can use the impulse theorem, which states that the impulse is equal to the change in momentum of the car:

`I = \Delta p\\F \Delta t = m \Delta v`

where

F is the average breaking force

`\Delta t = 5 s` is the stopping time

m = 1000 kg is the mass of the car

`\Delta v = -10 m/s` is the change in velocity of the car

Solving the equation for F,

`F=(m \Delta v)/(\Delta t)=((1000 kg)(-10 m/s))/(5 s)=-2000 N`