Final answer:
To find the greatest number of neon tetra fish Sahil can put in his tank, we need to calculate the volume of the tank and then divide it by the volume required for each fish.
Step-by-step explanation:
To find the greatest number of neon tetra fish Sahil can put in his tank, we need to calculate the volume of the tank and then divide it by the volume required for each fish. The volume of a cuboid can be found using the formula: Volume = length x width x height.
In this case, the volume of the tank is 55 cm x 28 cm x 33 cm = 50940 cm³. Since 1 liter is equal to 1000 cm³, Sahil needs 4 liters of water for each fish, which is equivalent to 4000 cm³ per fish.
Therefore, the greatest number of neon tetra fish Sahil can put in his tank is 50940 cm³ / 4000 cm³ = 12.735 fish. Since we cannot have a fraction of a fish, the greatest whole number of neon tetra fish Sahil can put in his tank is 12 fish.