Answer: 42.9%
Explanation:
From the given table , the number of part-time jobs =6+8 = 14
Total jobs = 6+8+9+2=25
Let A be the event of selecting a part time job , then
![P(A)=(14)/(25)](https://img.qammunity.org/2020/formulas/mathematics/high-school/k7girjic7tpotjboe7w91i47p6nvoma6n3.png)
Let B be the event of selecting a job where experience is needed.
The number of part time job openings where experience is needed =
![A\cap B=6](https://img.qammunity.org/2020/formulas/mathematics/high-school/bogm3m0pi9mqo00ks1i01qpdi6y03c67gk.png)
Then,
![P(A\cap B)=(6)/(25)](https://img.qammunity.org/2020/formulas/mathematics/high-school/rqhzjcw8frcijefqhjs6fixmk2sjlyqdxk.png)
Now, the probability that experience is needed for a randomly selected job opening, given that it is for part-time work is given by :-
![P(B|A)=(P(A\cap B))/(P(A))\\\\=((6)/(25))/((14)/(25))\\\\\\=(6)/(14)=0.428571428571](https://img.qammunity.org/2020/formulas/mathematics/high-school/2vkfo7baxfow0rw08f6o2q0ge4wwr38pob.png)
In percent,
![P(B|A)=0.428571428571*100=42.8571428571\%\approx42.9\%](https://img.qammunity.org/2020/formulas/mathematics/high-school/s2r16725j0l8yzl31i90d9reedwg50mvkr.png)