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Assuming a 90% confidence level, the margin of error is approximately?

Assuming a 90% confidence level, the margin of error is approximately?-example-1
User Catch
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6.3k points

2 Answers

6 votes

Answer:

0.3.

between 20.3 and 20.9

Explanation:

User Philip Walton
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6.1k points
5 votes

Answer:

0.3

Explanation:

The margin of error is calculated as ...

(standard deviation)/√(sample size) × (z*-score)

where the z*-score is chosen based on the desired confidence level.

Here, you have ...

  • standard deviation = 2.7
  • √(sample size) = √225 = 15
  • z*-score for 90% confidence level = 1.645

Putting these values in the above expression for margin of error gives ...

2.7/15·1.645 = 0.2961 ≈ 0.3

User Eyalb
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5.5k points