Question

A spinner has 6 equal sectors labeled A, B, C, D, E and F on it. The spinner is spun twice.

What is the probability of spinning B and then E, given that the spinner shows B on the first spin?

A. 1/2

B. 1/3

C. 1/6

D. 1/36

Answer 1

Answer: C. 1/6

Explanation:

Answer 2

Answer: C.
`(1)/(6)`

Explanation:

Given: A spinner has 6 equal sectors labeled A, B, C, D, E and F on it. The spinner is spun twice.

If it is given that the spinner shows B on the first spin, then the total outcomes will be{ (B,A), (B,B), (B,C), (B,D), (B,E), (B,F)}=6

The number of favorable outcome = 1

Now, the probability of spinning B and then E, given that the spinner shows B on the first spin=
`(1)/(6)`