Question

Julio has $2.75 in his pocket in nickels and dimes . The number of dimes is 10 less than twice the number of nickels. Find the number of each type of coin

Answer 1

Answer:Julio has 20 dimes and 15 nickels.

Explanation:

Solving this equation for n gives

0.1(2n−10)+0.05n0.25n−10.25nn=2.75=2.75=3.75=15

So, there are 15 nickels. Since the number of dimes is 10 less than twice the number of nickels, the number of dimes is 2(15)−10=20.

Julio has 20 dimes and 15 nickels.

Answer 2

A dime is worth 2 nickels.

let no of dimes be x

let no of nickles be y

so as per the data mentioned in the question , x=2*y-10

total amount = $2.75

so total amount should comprise of nickels and dimes

x*dimes + y*nickels = $2.75

x*( 2 nickels)+ y *nickels = $2.75

=> nickles( 2x+y) = $ 2.75

but 20 nickels = 1 dollar

nickles(2x+y) = 2.75*20 nickels

cancelling nickles on both sides

2x+y = 55

already we know that x= 2y-10

so 2(2y-10) +y= 55

4y-20+y=55

5y -20 =55

add 20 on both sides

5y-20+20=55+20

5y=75

divide with 5 on both sides

5y/5 =75/5

y= 15

so x= 2y-10

x= 2*15-10

x= 30-10

x= 20

so # of dimes =20

# of nickels =15